Question

if cos∅=7/24 sin(∅)sec​

Answer 1

Given,

Cos Ø = 7/24

b/h = 7k/24k

=> b = 7k

=> h = 24k

from Pythagorean theorem,

=> p = √h² - b²

=> p = √(24k)²-(7k)²

=> p = 22.9k (approx.)

Now,

SinØ SecØ = p/h x h/b

SinØ SecØ = 22.9k/24k x 24k/7k

SinØ SecØ = 22.9/7 Answer...