Question

If cos (90°

-A)=0, then Sin (A+B)=​

Answer 1

just understan don't copy

Explanation:

sin(90−θ)+cosθ=2cos(90−θ)⇒2cosθ=2sinθ⇒cotθ=21

we know that, cosec2θ=1−cot2θ⇒cosecθ=1+cot2θ⇒cosecθ=1+21=23

Therefore, Answer is 23

Answer 2

Answer:

sinB

Explanation:

cos(90-A)=0 then,

90-A=90

A=0

sinA= 0

sin(A+B)=SinA.CosB+CosA.SinB

=0.CosB+1.sinB

=sinB