Question

If cos 9x = sinx and 9x < 90 , then the value of x is​

Answer 1

Answer:

Step-by-step explanation:

Rewrite cos(9x) as sin(90° - 9x):

sin(90° - 9x) = sin(x)

Take arcsin of both sides (note x is between 0° and 10°, so we only have to solve for the first quadrant):

90° - 9x = x

10x = 90°

x = 9°

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Answer 2

cos9x=sinx

sin(90-9x)=sinx

90-9x=x

90=10x

10x=90

x=9

x=9 also satisfies the condition 9x<90

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