Question

If cos (a +) = 0, then sin (a -B) can be reduced to

Answer 1

Complete step-by-step answer:

It is given that 

cos(α+β)=0cos⁡(α+β)=0

.

Now, we know that the value of 

cos90∘=0cos⁡90∘=0

Hence, substituting the value of 0 in the RHS of 

cos(α+β)=0cos⁡(α+β)=0

, we get

 

⇒cos(α+β)=cos90∘⇒cos⁡(α+β)=cos⁡90∘

Cancelling cos function from both sides, we get

 

⇒(α+β)=90∘⇒(α+β)=90∘

Subtracting 

ββ

 from both sides, we get

 

α=