If cos A = 1/2 and sin B = 1/root 2, find the value of: tan A _tan B / 1+tan A tan B
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heya,..
cosA=1/2..
cosA=cos60°
A=60°
and again.SinB=1/√2
sinB=sin45°
B=45°
,now ,tanA-tanB/1+tanA*tanB=Tan(A-B)
tan(60°-45°)
tan15°=√3-1/√3+1 Ans
hope it help you.
@eajukumar☺
cosA=1/2..
cosA=cos60°
A=60°
and again.SinB=1/√2
sinB=sin45°
B=45°
,now ,tanA-tanB/1+tanA*tanB=Tan(A-B)
tan(60°-45°)
tan15°=√3-1/√3+1 Ans
hope it help you.
@eajukumar☺
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