Question

if cos A=1/2 and sin B =1/root2 find the value of tanA-tanB/1+tanAtanB

Answer 1

cosA=1/2
cos60°=1/2
Therefore...
A=60°
Now sinB=1/√2
sin45°=1/√2
Therefore....B=45°
Now tanA-tanB/1+tanAtanB
tan60°-tan45°/1+tan60°tan45°
√3-1/1+√3
Therefore
answer= √3-1/√3+1
or 1.73-1/1.73+1
0.73/2.73=73/273(Ans)
Either √3-1/√3+1 Or 73/273.