If cos A = (1+x²)/(1-x²);
x is not equal to 1 or -1
is it possible or not ?justify your answer
Answers
Answered by
1
cosA=(1+x^2)/(1-x^2)
=> cosA-x^2.cosA=1+x^2
=>(cosA-1)=x^2 (1+cosA)
=> x^2=(cosA-1)/(cosA+1)
here we see LHS part is always positive term hence RHS is also always positive
but condition is (cosA +1) isn't equal to zero and cosA always greater then 1
this is satisfied when cosA always greater then 1
but we know cosA maximum value 1
hence
cosA=(1+x^2)/(1-x^2) isn't possible .
=> cosA-x^2.cosA=1+x^2
=>(cosA-1)=x^2 (1+cosA)
=> x^2=(cosA-1)/(cosA+1)
here we see LHS part is always positive term hence RHS is also always positive
but condition is (cosA +1) isn't equal to zero and cosA always greater then 1
this is satisfied when cosA always greater then 1
but we know cosA maximum value 1
hence
cosA=(1+x^2)/(1-x^2) isn't possible .
Similar questions
Economy,
8 months ago
English,
8 months ago
Hindi,
1 year ago
English,
1 year ago
Social Sciences,
1 year ago