Math, asked by gurjaramit44, 5 months ago

If Cos A = 2/3 then find the value of Sin A and Tan A.

Answers

Answered by sridevichintala51
6

Answer:

cos A=2/3

Step-by-step explanation:

(hyp)^=s^+s^

3^=s^+2^

9=s^+4

9-4=s^

5=s^

√5=s

sinA=opposite/hypotenuse=√5/3

tanA=opposite/adjacent=√5/2

Answered by qwsuccess
0

sinA= √5/3 and tanA= √5/2

Given:

cosA = 2/3

To Find:

Value of sinA and tanA

Solution:

We know that for a right-angled triangle

cosA= Base/ Hypotenuse _(1)

given, cosA= 2/3 _(2)

Comparing _(1) and (2)

Base= 2 and Hypotenuse= 3

Using Pythagoras Theorem

(Hypotenuse)²= (Base)²+ (Perpendicular)²

(3)²= (2)²+ P²

9= 4+ P²

P²= 9-4

P= √5

Using ratio formulas of sinA and tanA

sinA= Perpendicular/ Hypotenuse

Putting values of perpendicular and hypotenuse in the above formula

sinA= √5/3

Also tanA= Perpendicular/Base

tanA= √5/2

Hence, the value of sinA is √5/3, and the value of tanA is √5/2.

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