if cos A =2÷5 find the value of 4 +4 tan 2A
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i hope thats solving are right
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Let the triangle be ABC right angled at B .
AB=2
AC=5
BC=?
By pythagoras theorem ,
AC square = AB square +BC square
BC square = AC square - AB square
BC square = 5 square - 2 square
= 25 - 4
BC square = 21
Thus BC = ROOT 21
tan A = root 21/2
4 + 4 (root 21/2 ) (root 21 / 2)
4+21
25
Hence the value is 25
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