if cos A=2/5, find the value of 4+4tan *tanA
Answers
Answered by
335
cos A = 2/5
4+4tan *tanA
4+4tan²A
cos A = 2/5
1/sec A = 2/5
sec A = 5/2
4 + 4 tan²A
4( 1 + tan²A)
4 ( sec²A)
4(5/2)²
4 * 25 /4
25
4+4tan *tanA
4+4tan²A
cos A = 2/5
1/sec A = 2/5
sec A = 5/2
4 + 4 tan²A
4( 1 + tan²A)
4 ( sec²A)
4(5/2)²
4 * 25 /4
25
Answered by
123
haya!!
cosA=2/5=b/h
by Pythagoras theorm..
p=√h^2-b^2
=)√25-4
=),√21=)p=√21
tanA=p/b=√21/2
from LHS.
4+4tan^2A
=)4+4×[√21/2]^2
=)4+4*2 1/4
=)25 ans
hope it help you.
@rajukumar☺
cosA=2/5=b/h
by Pythagoras theorm..
p=√h^2-b^2
=)√25-4
=),√21=)p=√21
tanA=p/b=√21/2
from LHS.
4+4tan^2A
=)4+4×[√21/2]^2
=)4+4*2 1/4
=)25 ans
hope it help you.
@rajukumar☺
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