If cos a=2/5, find the vie of 4+4 tan square A
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4+4tan^2A
=4(1+tan^2A)
=4*cos^2A
=4*cos2×2/5....
=4(1+tan^2A)
=4*cos^2A
=4*cos2×2/5....
iliyasz:
tan ^2 = 1+ sec ^2a now =1+6.25= 7.25
Answered by
1
= 4+4×(21/2)(21/2)
= 4+441
= 445
= 4+441
= 445
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