if cos A = 3/5 ,find 9 cot A -1
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Answered by
3
CosA = 3/5 = b/h
b = 3 , h = 5 , p = ?
we know that,
h² = b² + p²
p² = h² +b²
p² = (5)²+(3)²= 25-9 = 16
p = ✓16 = 4cm
Therefore,
b = 3 , h = 5 , p = ?
we know that,
h² = b² + p²
p² = h² +b²
p² = (5)²+(3)²= 25-9 = 16
p = ✓16 = 4cm
Therefore,
rohiki1234:
no is it righrt
Answered by
2
hey... here's ur answer,
given,
cos A= 3/5
by using pyth. theorem,
cot A = 3/4
put value of cot A, in the equation.... so
9(3/4) -1
27/4 -1
27-4/4
✈ 23/4. is the final answer..
hope it will be cleared to uh :)
given,
cos A= 3/5
by using pyth. theorem,
cot A = 3/4
put value of cot A, in the equation.... so
9(3/4) -1
27/4 -1
27-4/4
✈ 23/4. is the final answer..
hope it will be cleared to uh :)
thankxxxxxxxxxxx
ur welcome :)
if ur satisfied then mark as brainliest :-)
noo you are wrong
cos A =3/5 , B/H by the pythagoras theorem so, AB is find 4 And cos A=3/5 , B/H and Cot A= 3/5 , B/P and Cot A-1=9/12 so, 9 cot A-1= 9 multiple 9/10 -1 we find 81 /16 -1 so, l.c.m is 81-16/16 = 65/16
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