if cos A = 3/root 10 , cos B = 2/root 3, A and B are positive acute angles , then the value of (A+B) is ?
Answers
Answered by
1
Step-by-step explanation:
sinA=
10
1
⇒A=sin
−1
(
10
1
)
sinB=
5
1
⇒B=sin
−1
(
5
1
)
Now,
A+B=sin
−1
(
10
1
)+sin
−1
(
5
1
)
As we know that,
sin
−1
A+sin
−1
B=sin
−1
(A
1−B
2
+B
1−A
2
)
∴A+B=sin
−1
(
10
1
1−
5
1
+
5
1
1−
10
1
)
A+B=sin
−1
(
50
2
+
50
3
)
⇒A+B=sin
−1
(
50
5
)
⇒A+B=sin
−1
(
2
1
)
⇒A+B=
4
π
(∵A and B are positive acute angles)
Hence the correct answer is
4
π
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Answered by
5
Use principle/ general solution
to find Sin A and sin B
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