Question

if cos a= 4/5, prove that tan a upon 1+ tan square a = sin a upon seca
​

Answer 1

cos a=4/5

sin a=√1-(4/5)^2

=3/5

now,tan a=sin a/cos a=3/4

now,

LHS- tan a/1+(tan a)^2

=3/4/1+(3/4)^2

=3/4/1+9/16

= 3/4/16+9/16

=3*16/4*25=12/25

RHS- sin a/sec a=sin a*cos a

=3*4/5*5

=12/25=LHS

Hence LHS=RHS(proved)

Answer 2

above answer is correct

follow me..✌️