if cos A=9/41 then find all T-ratios
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Step-by-step explanation:
→ Given , cos A = 9/41 = B/H
→ Thus, B = 9 & H = 41
→ By Pythagoras Theorem,
→ H² = P² + B²
→ P² = H² - B²
→ P² = (41)² - (9)²
→ P² = 1681 - 81
→ P² = 1600
→ P = √1600 => P = 40
→ Now, sin A = P/H = 40/41
cos A = B/H = 9/41 (Given)
tan A = P/B = 40/9
cot A = B/P = 9/40
sec A = H/B = 41/9
cosec A = H/P = 41/40
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Answer:
Cos = 9/41 = b/h
Sin = 40/41 = p/h
Tan = 40/9 = p/b
Sec = 41/9 = h/b
Cosec = 41/40 = h/p
Cot = 9/40 = b/p
Step-by-step explanation:
Sin2 = 1 - cos2
= sin = 40/41
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