Question

If cos(a+B)=0 find sin(a+B) ?

Pls help it’s urgent

Answer 1

cos ( A + B ) = 0

But we know that, Cos 90° = 0

So,

cos ( A + B) = cos 90°

On comparing,

A + B = 90° -----(i)

So ,

sin ( A + B ) = sin 90° ( because from eq(i) , A + B = 90° )

=> Sin ( A + B ) = 1

Answer 2

Step-by-step explanation:

cos(a+B)=O

→ cos(a+B)=cos90°

→ a+B = 90°

Now, put the value of a+B = 90° .

sin(a+B)

→sin90°

→ 1 ( we know that sin90°=1)

★ Value of sin(a+B) = 1.