Math, asked by prerak42, 1 year ago

If cos A=b/a
-, where a and b are real numbers, find the value of sin^2A.​

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Answered by ghazalajamal685
1

Step-by-step explanation:

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Answered by Anonymous
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Sin 2A = 2SinA .CosA

=======2×root(a^2 - b^2)/a × b/a

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