if Cos A equal to 12 by 3 then find sin and tin A
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At first cos A = adj./ hyp.
therefore = 12/3
then find the other side by Pythagoras theorem..
Ac^2 = AB^2+BC^2
= 12^2+3^2
AC= √144+9
= √153
=12.36
sinA = opp./hyp.
= 12.36/3
tanA= opp./adj.
= 12.36/12
hope this answer helps you....
Pls mark my answer as the BRAINLIEST one
therefore = 12/3
then find the other side by Pythagoras theorem..
Ac^2 = AB^2+BC^2
= 12^2+3^2
AC= √144+9
= √153
=12.36
sinA = opp./hyp.
= 12.36/3
tanA= opp./adj.
= 12.36/12
hope this answer helps you....
Pls mark my answer as the BRAINLIEST one
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