If cos -sin = root2(sin) then prove that cos+sin = root2(cos)
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Answered by
439
cos-sin =√2 sin
squaring both sides
(cos-sin)²= (√2sin)²
cos²+sin²-2cossin = 2sin²
cos²= 2sin²-sin²+2 cos sin
cos² = sin²+2cos sin
Adding cos both sides
cos²+cos² = sin²+2cos sin +cos²
2cos² = (sin+cos)²
√(2cos²) = sin +cos
√2 cos = cos + sin
Hope it helps !
squaring both sides
(cos-sin)²= (√2sin)²
cos²+sin²-2cossin = 2sin²
cos²= 2sin²-sin²+2 cos sin
cos² = sin²+2cos sin
Adding cos both sides
cos²+cos² = sin²+2cos sin +cos²
2cos² = (sin+cos)²
√(2cos²) = sin +cos
√2 cos = cos + sin
Hope it helps !
Answered by
119
Answer:
Step-by-step explanation:
Cos - sin = √2 sin
Cos = √2sin + sin
Cos = sin (√2 + 1)
Cos (√2 - 1) = sin (√2 + 1) (√2 - 1)
√2cos - cos = sin (2 - 1)
√2cos - cos = sin
Sin = √2cos - cos
Sin + cos = √2cos
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