If cos theta =1/√2,then cot theta=
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We assume theta=A.
CosA=1/√2
CosA=base/hypotenuse.
B=1,H=√2.
By Pythagoras theory
H^2=P^2+B^2
2=P+1
P=1.
Cot A=1/tanA
CotA = cosA/sinA
Cot A=B/H/P/H
Cot A =B/H×H/P
Cot A=1. Answer
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