Question

If cos theta 1 + cos theta 2 + cos theta 3 = 3 then sin theta 1 + sin theta 2 + sin theta 3 =?

Answer 1

Answer:

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Answer 2

Answer:

$sin\theta_1 + sin\theta_2 + sin\theta_3 = 0$

Step-by-step explanation:

Given that

$Cos \theta_1 +Cos \theta_2 +Cos \theta_3 =3$

We know that

$-1 \leq Cos \theta \leq 1$

Hence the given condition

$Cos \theta_1 +Cos \theta_2 +Cos \theta_3 =3$

is possible if

$Cos \theta_1 = Cos \theta_2 = Cos \theta_3 =1$

that is when,

$\theta_1 = \theta_2 = \theta_3 = {n\pi }$

Hence if  $\theta_1 = \theta_2 = \theta_3 = {n\pi }$ then,

$sin\theta_1 = sin\theta_2 = sin\theta_3 = 0$

$sin\theta_1 + sin\theta_2 + sin\theta_3 = 0$$sin\theta_1 + sin\theta_2 + sin\theta_3 = 0$

Hence $sin\theta_1 + sin\theta_2 + sin\theta_3 = 0$