Question

if cos theta =-3/5 find sin theta and tan theta where theta is an angle in third quadrant​

Answer 1

Step-by-step explanation:

cos

$cos ^{2} + sin^{2} = 1$

:• (-3/5)^2 +sin^2 = 1

:• 9/25 + sin^2 = 1

sin^2 = 1-9/25

sin^2 = 25/25 -9/25

sin^2 = 16/25

sin 0 = 4/5

tan 0 = sin 0 / cos 0

tan 0 = 4/5 × 5/-3

tan 0 = -20/12

tan 0 = -4/3