if cos theta =3/5,find value of 2tan theta-cot theta/3seca thet+4cosec theta
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Answered by
1
Answer:
answer is-149/60
Step-by-step explanation:
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Answered by
2
Answer:
451/60
Step-by-step explanation:
Let this symbol ● be theta ..for convenience ..likhne me aasani hogi
cos ● = 3/5 = base/hypotenus or b/h
we know, h² = p² + b²
So, p² = h² - b²
p² = 25 - 9 = 16
therefore, p = 4
Now lets find the values of other trigonometric ratios
tan● = p/b = 4/3
cot● = b/p = 3/4
sec● = h/b = 5/3
cosec● = h/p = 5/4
We have been given the following expression to solve
2 tan● - cot●/3sec● +4cosec●
2×(4/3) - (3/4) / 3×(5/3) + 4×(5/4)
8/3 - 3/20 + 5
(160 - 9 + 300) / 60
451/60
I hope I didn't make any mistake ...
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