Question

If cos theta:sin theta= 1:2 find (8cos theta-2sin theta)/(4cos theta +2 sin theta)

Answer 1

if you want to ask any other questions you can ask from me

Answer 2

The value of given expression is 0.67.

Step-by-step explanation:

Since we have given that

$\dfrac{\cos \theta}{\sin \theta}=\dfrac{1}{2}$

So, Let cos θ = x

sin θ = 2x

So, we need to find the value of

$\dfrac{8\cos \theta-2\sin \theta}{4\cos \theta+2\sin \theta}$

So, it becomes,

$\dfrac{8\times x-2\times 2x}{4\times x+2\times 2x}\\=\dfrac{8x-4x}{4x+2x}\\\\=\dfrac{4x}{6x}\\\\=\dfrac{4}{6}\\\\=0.67$

Hence, the value of given expression is 0.67.

# learn more:

If sin theta + sin^2 theta + sin^3 theta= 1, prove that cos^6 theta -4cos^4 + 8cos^2=4

https://brainly.in/question/2316204