If cos theta + sin theta = a then sin 2theta
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Answered by
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sin A + cos A =a
squring both sides
(sin A +cosA)^2=a^2
sin^2A+cos^2A+2sinAcosA=a^2
1 + 2sinAcosA=a^2
2sinaAcosA=a^2-1
sin2A=a^2 -1
squring both sides
(sin A +cosA)^2=a^2
sin^2A+cos^2A+2sinAcosA=a^2
1 + 2sinAcosA=a^2
2sinaAcosA=a^2-1
sin2A=a^2 -1
Answered by
2
heya☺
cos¢+sin¢=a
squaring on both side first...
(cos¢+sin¢)^2=a^2
=)cos^2¢+sin^2¢+2sin¢*cos¢=a^2
=)2sin¢*cos¢=-1+a^2
=)sin2¢=a^2-1【2sin¢*cos¢=sin2】
hence ,sin2¢=a^2-1
hope it help you.
@rajukumar☺
cos¢+sin¢=a
squaring on both side first...
(cos¢+sin¢)^2=a^2
=)cos^2¢+sin^2¢+2sin¢*cos¢=a^2
=)2sin¢*cos¢=-1+a^2
=)sin2¢=a^2-1【2sin¢*cos¢=sin2】
hence ,sin2¢=a^2-1
hope it help you.
@rajukumar☺
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