If cos theta + sin theta = root 2 sin theta,show that sin theta - cos theta = root 2 cos theta.
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Here is your solution....
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Step-by-step explanation:
sin²A+cos²A=1 (a)
sinA+cosA=√2
let sinA-cosA =y
sin²A - cos²A =(sinA+cosA)(sinA-cosA)=√2 × y (b)
adding (a),(b)
2sin²A=√2y+1
===>y = (2sin²A -1)/√2 = (1-2cos²A)/√2 = -cos2A/√2
vamshimadineni123:
sorry there is a mistake in my answer
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