If cos theta -- sin theta =
![\sqrt{2} \ \sin \sqrt{2} \ \sin](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7D++%5C+%5Csin)
theta then prove that cos theta +sin theta ==
![\sqrt{2} \sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7D+)
cos theta
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