if cos tita = 4/5 then find the value of codec tita
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sin^2theta +cos^2theta = 1
thus, sin^2theta +(4/5)^2 = 1
sin^2theta = 1 - (4/5)^2
= 1 - 16/25
= 25/25 - 16/25
= 9/25
thus, sin theta = 3/5. ____taking square root
now cosec theta = 1/sin theta
thus,cosec theta = 1/3/5 _____which is 5/3
thus, cosec theta = 5/3
hope this helps you
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thus, sin^2theta +(4/5)^2 = 1
sin^2theta = 1 - (4/5)^2
= 1 - 16/25
= 25/25 - 16/25
= 9/25
thus, sin theta = 3/5. ____taking square root
now cosec theta = 1/sin theta
thus,cosec theta = 1/3/5 _____which is 5/3
thus, cosec theta = 5/3
hope this helps you
if yes then plz mark as brainliest
sakthishamifb:
cosec tita = i/sin tita not 1/ cos tita
yes
i wrote it by mistake
now i have corrected it
just have a look on original answer
Answered by
1
Answer:
5/3
Step-by-step explanation:
therefore cos^2 = 16/25
we know that cos^2=1-sin^2
=> 16/25=1-sin^2 => sin^2 =1-16/25
=9/25 => sin tita = 3/5
also cosec tita = 1/sin tita => cosec tita = 5/3
hope my answer was helpful
please mark me as brainliest
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