If cos x =-3/5 , x lies in the 3rd quadrant , find the values of cos x/2 , sin x/2 , tan x/2 and sin 2x.
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cos x = –3/5 sinx = 4/5
cos(x/2) = sqrt ((cosx+1)/2) = sqrt ((–3/5+1)/2) = sqrt (1/5)
sin(x/2) = sqrt ( 1–cos²(x/2)) = sqrt (4/5)
tan(x/2) = 2
sin2x = 2 sinx cosx = –24
cos(x/2) = sqrt ((cosx+1)/2) = sqrt ((–3/5+1)/2) = sqrt (1/5)
sin(x/2) = sqrt ( 1–cos²(x/2)) = sqrt (4/5)
tan(x/2) = 2
sin2x = 2 sinx cosx = –24
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