if cos²0=0.64, what is the value of 1)sin²0.2)sin0 (0 is theta) write full answer
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Cos²θ = 64/100
Cos θ = 8/10
Cos θ = Adjacent side / Hypotenuse
Therefore,
Opposite side = √Hypotenuse²-Adjacent side²
= √100-64
=√36
=±6
=6 {Distance cannot be negative}
Therefore,
Sin θ = Opposite Side / Hypotenuse = 6/10
Sin² θ = 36/100 = 0.36
OTHER METHOD :
We know,
Sin² θ + Cos² θ = 1
therefore,
Sin² θ = 1 - Cos² θ
= 1 - 0.64
=0.36
Sin²θ = 36/100
Sin θ = 6/10 = 0.6
Hope it Helps
ʍolloℲ
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