If Cos²x = 1/3, then cos4x=?
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Formula of cos 4x, ie you need the angle in x form…
Since, we know cos 2x = cos²x - sin²x & sin2x = 2sinxcosx
By applying the above..
So, cos 4x
= cos 2*2x
= cos² 2x - sin² 2x
= ( cos 2x)² - (sin 2x)²
= ( cos²x - sin²x )² - (2sinx*cosx)²
= cos^4 x + sin^4 x- 2sin²x.cos²x - 4 sin²x*cos² x
= cos^4(x) + sin^4(x) - 6 sin²xcos²x
PS! Since Formula is asked. It can be expressed in the t- ratios of any reduced angle form….
Since, we know cos 2x = cos²x - sin²x & sin2x = 2sinxcosx
By applying the above..
So, cos 4x
= cos 2*2x
= cos² 2x - sin² 2x
= ( cos 2x)² - (sin 2x)²
= ( cos²x - sin²x )² - (2sinx*cosx)²
= cos^4 x + sin^4 x- 2sin²x.cos²x - 4 sin²x*cos² x
= cos^4(x) + sin^4(x) - 6 sin²xcos²x
PS! Since Formula is asked. It can be expressed in the t- ratios of any reduced angle form….
Answered by
0
hope its help
i have applied only one formula here
that is cos 2x = 2cos^2x - 1
and have a good day
i have applied only one formula here
that is cos 2x = 2cos^2x - 1
and have a good day
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