Question

if cosA=1/2 and sinB=1/2 find sin(A+B)..........????​

Answer 1

Solution

Cos A=1 /2

therefore....SinA=√(1-Cos²A)=√(1-(1/2)²)=√3/2

sinB=1/2

therefore...CosB=√(1-Sin²B)=√(1-(1/2)²)=√3/2

now.....

Sin(A+B)=SinA Cos B+CosA SinB

=(√3/2)(√3/2)+(1/2)(1/2)

=(3/4)+(1/4)

=4/4=1

Answer 2

Answer:

sin (A+B) = 1

Step-by-step explanation:

cos A = ½

cos 60° = 1/2

so A = 60°

sin B = ½

sin 30° = ½

so B = 30°

(A+B) = 60+30 = 90°

sin 90° = 1