Question

If cosA=1/2 and tanB=1/root3 then find sin(A+B) whereA and B are acute angles

Answer 1

CosA=1/2
Cos60°=1/2
A=60
TanB=1/sq.rt3
Tan30=1/sq.rt3
B=30
Sin (A+B)=sin (60+30)
=sin90°=1
Therefore,
Sin(A+B)=1
Thank you

Answer 2

Cos A = to 1 by 2
but Cos 60 = 1 by 2
: A = 60
Tan B = 1 by root 3
but Tan 30 = 1 by root 3
: B = 30
Sin(A + B) = sin 90 = 1

HOPE THIS WILL HELP U :)