If cosA=1/2 and tanB=1/root3 then find sin(A+B) whereA and B are acute angles
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Answered by
32
CosA=1/2
Cos60°=1/2
A=60
TanB=1/sq.rt3
Tan30=1/sq.rt3
B=30
Sin (A+B)=sin (60+30)
=sin90°=1
Therefore,
Sin(A+B)=1
Thank you
Cos60°=1/2
A=60
TanB=1/sq.rt3
Tan30=1/sq.rt3
B=30
Sin (A+B)=sin (60+30)
=sin90°=1
Therefore,
Sin(A+B)=1
Thank you
Answered by
11
Cos A = to 1 by 2
but Cos 60 = 1 by 2
: A = 60
Tan B = 1 by root 3
but Tan 30 = 1 by root 3
: B = 30
Sin(A + B) = sin 90 = 1
HOPE THIS WILL HELP U :)
but Cos 60 = 1 by 2
: A = 60
Tan B = 1 by root 3
but Tan 30 = 1 by root 3
: B = 30
Sin(A + B) = sin 90 = 1
HOPE THIS WILL HELP U :)
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