Question

If cosA = 1/2 ,find the value of 2secA/1+tan²A

Answer 1

Hi ,

cos A = 1/2 ---( 1 )

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We know that ,

1 ) 1 + tan² A = sec² A

2 ) 1/secA = cos A

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Value of 2secA/( 1 + tan² A )

= 2secA/ sec² A

= 2/secA

= 2cosA

= 2 × 1/2

= 1

I hope this helps you.

: )

Answer 2

Cos a = 1/2 =b/h

Let, b=k(1k),h=2k

p=√h^2-b^2

p=√4k^2-k^2

p=√3k^2

p=√3 k

Sec a=h/b=2

Tan a =p/b=√3

2sec a = 4 & 1+ tan^2 a=4

So, 4/4=1 (ans)

Answer of this question is 1...