Question

plz answer this algebra

Answer 1

The answer goes like this
=> 250(a-b)³+2
=> 250(a³-3a²b+3ab²-b³)+2
=> 250a³-750a²b+750ab²-250b³+2
=> 250(a³-b³)-750(a²b-ab²)+2
=> 250(a³-b³)-750(a²b-ab²) = -2
=> 250(a³-b³)+(a²b-ab²) = 1/375
=> (a³-b³)+(a²b-ab²) = 2/3
=> (a-b)(a²+ab+b²+a²b-ab²) = 2/3
=> a(a²+ab+b²+a²b-ab²)-b(a²+ab+b²+a²b-ab²) = 2/3
=> a³+a²b+ab²+a³b+a²b²-a²b-ab²-b³-a²b²+ab³ = 2/3
=> a³-3a³b+3ab³-b³ = 2/3
=> (a-b)³ = 2/3
=> a-b = ³√(2/3)