Question

if cosA=1/2,find the values of 2seca/1+$tan^{2}$A

Answer 1

Step-by-step explanation:

$Given: \: cos A \: = \frac{1}{2} \\ \frac{2 \: sec \: A}{1 + {tan}^{2} \: A } \\ = \frac{2 \: sec \: A}{ {sec}^{2} \: A }..... (\because 1 + {tan}^{2} \theta = {sec}^{2} \theta) \\ = \frac{2 }{ {sec} \: A } \\ = 2cos A \\ = 2 \times \frac{1}{2} \\ = 1$