If cosA =12/13, then find the value of tanA
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Answered by
1
hey sakna here
cosA = 12/13
bt we know that
cos A = Base / hypotenuse
base = 12
hypotenuse = 13
bt tan A = Perpendicular / base
so
perpendicular = 5
tan A = 5/12
Answered by
1
cos A=b/h
where b is base and h is hypotenuse
so b/h=12/13
so let b =12x and h= 13x
we take them as x and not simply 12 or 13 as they could have been divided and then would have come 12 and 13
in a right angle triangle
acc to pyth theorem
h^2=p^2+b^2
(13x)^2=p^2+(12x)^2
25x^2=p^2
p=5
so tan a =p/b
tana =5/12
where b is base and h is hypotenuse
so b/h=12/13
so let b =12x and h= 13x
we take them as x and not simply 12 or 13 as they could have been divided and then would have come 12 and 13
in a right angle triangle
acc to pyth theorem
h^2=p^2+b^2
(13x)^2=p^2+(12x)^2
25x^2=p^2
p=5
so tan a =p/b
tana =5/12
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