If cosA=2/3,find the of 4+4tan^2A
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Answered by
1
cosA=2/3
4+4tan^2=4(1+tan^2A)
=4sec^2A=4×3/2×3/2
=9
4+4tan^2=4(1+tan^2A)
=4sec^2A=4×3/2×3/2
=9
baarak2000:
are uh sure ??
yup
the ans is 25
how
that I don't know but the ans is 25
Answered by
1
CosA=b/h =2/3
AB²+BC²=AC²
=>AB²+2²=3²
=>AB²=9-4=5
=>AB=25
4+4Tan²A
=4+4(25/2)²
=4+4(125/4)
=4+125
=129
AB²+BC²=AC²
=>AB²+2²=3²
=>AB²=9-4=5
=>AB=25
4+4Tan²A
=4+4(25/2)²
=4+4(125/4)
=4+125
=129
I think its wrong
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