If cosA =2/5,find the value of 4 +4tan^2A
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4(1+tan²A)=4sec²A=4/cos²A=4/(4/25)=25
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4 + 4 tan^2A
4(1+ tan^2)
4 × sec^2
4 × 1/cos ^2
4 × 1/2^2/5^
25 ans....
I hope it help you
4(1+ tan^2)
4 × sec^2
4 × 1/cos ^2
4 × 1/2^2/5^
25 ans....
I hope it help you
Aasthakatheriya1:
ur welcome
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