if cosA = 2/5, find the value of 4+4tan square A
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Answered by
1
Answer:
25
Step-by-step explanation:
W.K.T
sin²A + cos²A = 1
==>sin²A + (2/5)² = 1
==>sin²A+ 4/25=1
==>sin²A=1-4/25
==>sinA=√(21/25)
Now,
4 + 4tan²A
= 4 + 4(sin²A/cos²A)
=4+4[(21/25)/(4/25))]
=4+ 4[21*25/25*4]
= 4+ 4[21/4]
=4 + 21
=25
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