Question

If cosA
2 then find the value of sinA
then find the value of sinA + tanA​

Answer 1

Answer:

(3/2) √3 or 3√3/2

Step-by-step explanation:

cosine of any angle can never be greater than 1 and lesser than - 1.

Assuming it your mistake, let cosA = 1/2.

⇒ cosA = 1/2

    using sin²x + cos²x = 1

⇒ sin²A + (1/2)² = 1

⇒ sinA = √(1 - 1/4) = √3/2

Thus, tanA = sinA/cosA = (√3/2)(1/2)

                  = √3

∴ sinA + tanA = √3/2 + √3  

                       = √3(1/2 + 1)

                       = 3√3/2

Answer 2

Given:-

• If cosA2 then find the value of sinAthen find the value of sinA + tanA

To Find:-

• The value of sinA + tanA

Solution:-

• Consine os any angle can never be greater than 1 and lesser than -1

$\color{red} \huge \bf \boxed {correct \: question \:let \: cosA \: = \: 1/2}$

$= > cosA \: = \frac{1}{2} \\ \bf \color{red} \big using \: {sin}^{2}x + {cos}^{2} x = 1 \\ = > {sin}^{2} A + {(\frac{1}{2} )}^{2} = 1 \\ = > \: sinA = \sqrt{( \frac{1 - 1}{4} )} = \sqrt{ \frac{3}{2} } \\ thus \: \: \: tanA = \frac{sinA}{cosA} = ( \sqrt{ \frac{3}{2} } \:)( \frac{1}{2} ) \\ = \sqrt{3} \\ sinA + tanA = \sqrt{ \frac{3}{2} } + \sqrt{3} \\ = \sqrt{3} ( \frac{1}{2} ) + 1) \\ = 3 \sqrt{ \frac{3}{2} }$

@MrsGoodGirl•••••••••••••••