If cosA =√3/2 find the value of tan (A/2)
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Answer:
√3
cos A = √3/2 cos 60°= √3/2
let us solve,
A = 60°
tan 60°=√3
then,
2tanA/(1+tan A)(1-tan A)..
putting tan A value in ....[1]
we get,
..[1]
=2x√3/{1+√3}{1-√3}
= 2√3/1-√3+√3-3
= 2√3/2+0
= 2√3/2
= √3
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