Question

If cosA=9/41 then sinA=​

Answer 1

Step-by-step explanation:

cosA= 9/41 = adj/hypo

sin A= opp/hyp

ac²=ab²+bc²

9²=41²+bc²

81=1681+bc²

bc²=1681-81

bc²=1600

bc=√1600

bc=40

SinA= opp/hypo= 40/41