If cosa +cosb+cosc = 0 then the value of k so that cos3a +cos3b + cos3c =k(cosa.cosb.cosc)
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3(cosa+cosb+cosc)=k(cosa.cosb.cosc)
3(0)=k(cosa.cosb.cosc)
0=k(cosa.cosb.cosc)
k=0/(cosa.cosb.cosc)
k=0
3(0)=k(cosa.cosb.cosc)
0=k(cosa.cosb.cosc)
k=0/(cosa.cosb.cosc)
k=0
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