If cosec(theta)=25/24 then find sin^2(theta)+cos^2(theta)
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Answered by
0
always sin^2(theta)+cos^2(theta)= 1
look
given that cosec(theta)=25/24
so sin(theta)=24/25
so sin^2(theta)=576/625
by this we can get cos^2(Theta)=47/625
therefore sin^2(theta)+cos^2(theta)=576/625+47/626=625/625=1
look
given that cosec(theta)=25/24
so sin(theta)=24/25
so sin^2(theta)=576/625
by this we can get cos^2(Theta)=47/625
therefore sin^2(theta)+cos^2(theta)=576/625+47/626=625/625=1
Answered by
0
cosec∅ = 25/24
we know that cosec∅ = hypotenuse / opposite side to ∅.
Hypotenuse ²- opposite side²=adjacent side²
25²-24²=adjacent side
adjacent side =√49=7
Now,sin∅=24/25
cos∅=7/25
sin²∅+cos²∅
=(24/25)²+(7/25)²
=576+49/625
=625/625
=1
sin²∅+cos²∅=1
we know that cosec∅ = hypotenuse / opposite side to ∅.
Hypotenuse ²- opposite side²=adjacent side²
25²-24²=adjacent side
adjacent side =√49=7
Now,sin∅=24/25
cos∅=7/25
sin²∅+cos²∅
=(24/25)²+(7/25)²
=576+49/625
=625/625
=1
sin²∅+cos²∅=1
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