Question

If cosA+cosB+cosC=3 Then sinA*sinB*sinC=??

Answer 1

CosA=1
CosB=1
CosC=1
Therefore the sum is 3
Therefore A = B = C = 90
CosA=90 =0
CosB=90 =0
CosC=90 =0
I think it is the answer to the question