If cosA is equal to 2 by 3 find the value of 4 + 4tan2A
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4+4tan2A
=4(1+tan2A)
cosA=2/3
=adjacent/hypotenuse
AB=2
AC=3
AC^2=AB^2+BC^2
3^2-2^2=BC^2
BC=√9-4
=√5
4(1+tan2A)
=4(1+√5/2×2)
=4(1+√5)
=4(1+tan2A)
cosA=2/3
=adjacent/hypotenuse
AB=2
AC=3
AC^2=AB^2+BC^2
3^2-2^2=BC^2
BC=√9-4
=√5
4(1+tan2A)
=4(1+√5/2×2)
=4(1+√5)
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