Question

if cosA = ncosbeta and sinA=msinbeta show that (m^2 - n^2)sin^2beta
= 1-n^2​

Answer 1

Answer:

If cosA/cosB = n and sinA/sinB = m, then (m2 - n2)sin2B = ? (1) 1 – n2 (2) 1 + n2 (3) 1 – n (4) 1 + nRead more on Sarthaks.com - https://www.sarthaks.com/205396/if-cosa-cosb-n-and-sina-sinb-m-then-m-2-n-2-sin-2b-1-1-n-2-2-1-n-2-3-1-n-4-1-n