If cosA + sin B = m and sin A + cos B = n, prove that 2sin (A+B)=m square+ n square-2
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Answer:
proved
Step-by-step explanation:
cosA + sin B = m and sin A + cos B = n,
(cosA + sin B)² = m²
( sin A + cos B )² = n²
cos²A + sin² B + 2 cosA sin B =m²
sin² A + cos² B + 2sin A cos B = n²
2 + 2 sin ( A + B ) = m² + n²
2 sin ( A + B ) = m² + n² - 2
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