Question

what is the distance between the points (2,1) and (14,6) on a coordinate plane?

Answer 1

distance^2 = (14-2)^2 + (6-1)^2
= 144 + 25 = 169
distance = 169^(1/2) = 13

Answer 2

Answer:

13

Step-by-step explanation:

let distance be PQ

PQ^2= (14-2)^2+(6-1)^2

PQ^2= 12^2+5^2

PQ^2= 144+25

PQ= √169

PQ= 14